Multifractals in ecology using R - Day 2
Posgraduate course, University of Maringá, 2013
Cumulative distributions and ranks
We want to make a plot of the cumulative distribution of a function $P(x)$ the frequency of words in a text.
The cumulative distribution of the frequency is defined such that $P(x)$ is the fraction of words with frequency greater than or equal to $x$.
If $x$ is the frequency of the most frequent word, usually “the”, then there is exactly one word with frequency greater than or equal to $x$.
Similarly for the second most frequent word, usually “of”, there are two words with frequency greater than or equal: “of” and “the”.
Cumulative distributions and ranks 1
In general if we rank the words in descending order then by definition there are n words with frequency greater than or equal than that of the nth most commond word.
Thus the cumulative distribution $P(x)$ is proportional to the rank n of a word.
Then to plot $P(x)$ we only need to plot the ranks as a function of the frequency.
Cumulative distributions and fractal dimension
- We can analyze the data from Metzler (1992)
rm(list=ls()) ps <- read.table("patch1968.dat",header=T) ps$r <- rank(-ps$pSize) plot(r ~ pSize,data=ps) plot(log(r)~log(pSize),data=ps) lm0 <- lm(log(r)~log(pSize),data=ps) summary(lm0) abline(lm0)
Cumulative distributions and fractal dimension 1
- If $B$ is the exponent then $H = 2 - 2B$
slope0 <- coef(lm0)[2] 2+slope0*2
The patches are persistent because H=1.18 > 0.5
- We need to install the package “car” to test for autocorrelation with the Durbin-Watson statistic. We can do this using the RStudio menu Tools/Install Packages.
require(car) dwt(lm0)
we can draw a grid to determine the break point.
grid()
Exercise 1
Split the data in two to obtain two fractal dimensions without correlation
There is a shorcut for doing this: the package “segmented” fits a broken line and finds the break point.
require(segmented) ps$logr <- log(ps$r) ps$logpSize <- log(ps$pSize) lm0 <- lm(logr~logpSize,data=ps) seg <- segmented(lm0, seg.Z = ~logpSize, psi=4) summary(seg) slope(seg)
Exercise 1 (Cont.)
Let’s do a function to calculate H
- small patches are persistent
calcH <- function(B) { 2-2*abs(B)} calcH(.1550) # H = 1.69
Big patches are anti-persistent
calcH(.9036) # H = 0.19
What is the breakpoint value in ha? Let’s do another function.
- A possible answer:
calcBreak <- function(B) { 0.1*exp(B)*0.65 } calcBreak(3.35) # 1.85 ha
Conclusion
small patches: if they are growing they keep growing, if they are reducing they vanish.
big patches: if they are growing they will reduce, if they are reducing they will grow.
Thus big patches are more stable, small patches appear and disappear.
Exercise 2
Let’s do the same thing using segmented with the 1985 data: “patch1985.dat”
- We can do a plot with the segmented object
plot(seg,col="green",xlab="Log Patch Size" ,ylab="Acum Freq") points(log(r)~log(pSize),data=ps,pch=2,cex=.5)
- We can use the functions:
summary(seg) slope(seg) calcH(0.2676) calcH(1.26) calcBreak(2.708) # 0.97 ha
A different graphic analysis
- Using graphics package “ggplot2”. We need to add both datasets in one data frame
ps <- read.table("patch1985.dat",header=T) ps$r <- rank(-ps$pSize) ps$Year <- "1985" ps1 <- read.table("patch1968.dat",header=T) ps1$r <- rank(-ps1$pSize) ps1$Year <- "1968" ps <- rbind(ps,ps1)
Gramar of graphics ggplot2
require(ggplot2)
ggplot(data=ps,aes(x=pSize,y=r,color=Year))
+geom_point()
p <- ggplot(data=ps,aes(x=log(pSize),y=log(r),
color=Year))+geom_point(aes(shape=Year))
More questions
- This seems a fragmentation process the frequency of small patches increases but the scaling of big patches seems similar, have big patches different scalings?
ps$logpSize <- log(ps$pSize) ps1 <- ps[ps$logpSize>3.35,] p + geom_smooth(data=ps1,method="lm") ggsave("patch_Breaks.png",width=2)